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72t-4.9t^2+324=0
a = -4.9; b = 72; c = +324;
Δ = b2-4ac
Δ = 722-4·(-4.9)·324
Δ = 11534.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-\sqrt{11534.4}}{2*-4.9}=\frac{-72-\sqrt{11534.4}}{-9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+\sqrt{11534.4}}{2*-4.9}=\frac{-72+\sqrt{11534.4}}{-9.8} $
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